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3x^2+4x^2=30^2
We move all terms to the left:
3x^2+4x^2-(30^2)=0
We add all the numbers together, and all the variables
7x^2-900=0
a = 7; b = 0; c = -900;
Δ = b2-4ac
Δ = 02-4·7·(-900)
Δ = 25200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{25200}=\sqrt{3600*7}=\sqrt{3600}*\sqrt{7}=60\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{7}}{2*7}=\frac{0-60\sqrt{7}}{14} =-\frac{60\sqrt{7}}{14} =-\frac{30\sqrt{7}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{7}}{2*7}=\frac{0+60\sqrt{7}}{14} =\frac{60\sqrt{7}}{14} =\frac{30\sqrt{7}}{7} $
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